Simplify bn2vch using int.to_bytes

pull/764/head
Pieter Wuille 5 years ago committed by Pieter Wuille
parent a421e0a22f
commit a3ad6459b7

@ -27,38 +27,14 @@ def hash160(s):
def bn2vch(v): def bn2vch(v):
"""Convert number to bitcoin-specific little endian format.""" """Convert number to bitcoin-specific little endian format."""
# The top bit is used to indicate the sign of the number. If there # We need v.bit_length() bits, plus a sign bit for every nonzero number.
# isn't a spare bit in the bit length, add an extension byte. n_bits = v.bit_length() + (v != 0)
have_ext = False # The number of bytes for that is:
ext = bytearray() n_bytes = (n_bits + 7) // 8
if v.bit_length() > 0: # Convert number to absolute value + sign in top bit.
have_ext = (v.bit_length() & 0x07) == 0 encoded_v = 0 if v == 0 else abs(v) | ((v < 0) << (n_bytes * 8 - 1))
ext.append(0) # Serialize to bytes
return encoded_v.to_bytes(n_bytes, 'little')
# Is the number negative?
neg = False
if v < 0:
neg = True
v = -v
# Convert the int to bytes
v_bin = bytearray()
bytes_len = (v.bit_length() + 7) // 8
for i in range(bytes_len, 0, -1):
v_bin.append((v >> ((i - 1) * 8)) & 0xff)
# Add the sign bit if necessary
if neg:
if have_ext:
ext[0] |= 0x80
else:
v_bin[0] |= 0x80
v_bytes = ext + v_bin
# Reverse bytes ordering for LE
v_bytes.reverse()
return bytes(v_bytes)
_opcode_instances = [] _opcode_instances = []
class CScriptOp(int): class CScriptOp(int):

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