Always enforce lock strict lock ordering (try or not)

pull/9674/head
Matt Corallo 8 years ago
parent fd13eca147
commit 8465631845

@ -77,52 +77,28 @@ boost::thread_specific_ptr<LockStack> lockstack;
static void potential_deadlock_detected(const std::pair<void*, void*>& mismatch, const LockStack& s1, const LockStack& s2)
{
// We attempt to not assert on probably-not deadlocks by assuming that
// a try lock will immediately have otherwise bailed if it had
// failed to get the lock
// We do this by, for the locks which triggered the potential deadlock,
// in either lockorder, checking that the second of the two which is locked
// is only a TRY_LOCK, ignoring locks if they are reentrant.
bool firstLocked = false;
bool secondLocked = false;
bool onlyMaybeDeadlock = false;
LogPrintf("POTENTIAL DEADLOCK DETECTED\n");
LogPrintf("Previous lock order was:\n");
BOOST_FOREACH (const PAIRTYPE(void*, CLockLocation) & i, s2) {
if (i.first == mismatch.first) {
LogPrintf(" (1)");
if (!firstLocked && secondLocked && i.second.fTry)
onlyMaybeDeadlock = true;
firstLocked = true;
}
if (i.first == mismatch.second) {
LogPrintf(" (2)");
if (!secondLocked && firstLocked && i.second.fTry)
onlyMaybeDeadlock = true;
secondLocked = true;
}
LogPrintf(" %s\n", i.second.ToString());
}
firstLocked = false;
secondLocked = false;
LogPrintf("Current lock order is:\n");
BOOST_FOREACH (const PAIRTYPE(void*, CLockLocation) & i, s1) {
if (i.first == mismatch.first) {
LogPrintf(" (1)");
if (!firstLocked && secondLocked && i.second.fTry)
onlyMaybeDeadlock = true;
firstLocked = true;
}
if (i.first == mismatch.second) {
LogPrintf(" (2)");
if (!secondLocked && firstLocked && i.second.fTry)
onlyMaybeDeadlock = true;
secondLocked = true;
}
LogPrintf(" %s\n", i.second.ToString());
}
assert(onlyMaybeDeadlock);
assert(false);
}
static void push_lock(void* c, const CLockLocation& locklocation, bool fTry)

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