build: fix x86_64 asm detection for some compilers

I Noticed this on OSX with clang, though it likely happens elsewhere as well.
The result is disabled x86_64 asm.

Due to missing escaping, this $0 was interpreted as the function name
SECP_64BIT_ASM_CHECK, causing the compile-check to be broken on some compilers.

The actual check looked like this:

int main()
{
  uint64_t a = 11, tmp;
  __asm__ __volatile__("movq SECP_64BIT_ASM_CHECKx100000000,%1; mulq %%rsi" : "+a"(a) : "S"(tmp) : "cc", "%rdx");
  return 0;
}

It seems even more odd that it compiled anywhere.
pull/11871/head
Cory Fields 9 years ago
parent c18b869e58
commit 3f8fdfbec1

@ -3,13 +3,13 @@ AC_DEFUN([SECP_INT128_CHECK],[
has_int128=$ac_cv_type___int128
])
dnl
dnl escape "$0x" below using the m4 quadrigaph @S|@, and escape it again with a \ for the shell.
AC_DEFUN([SECP_64BIT_ASM_CHECK],[
AC_MSG_CHECKING(for x86_64 assembly availability)
AC_COMPILE_IFELSE([AC_LANG_PROGRAM([[
#include <stdint.h>]],[[
uint64_t a = 11, tmp;
__asm__ __volatile__("movq $0x100000000,%1; mulq %%rsi" : "+a"(a) : "S"(tmp) : "cc", "%rdx");
__asm__ __volatile__("movq \@S|@0x100000000,%1; mulq %%rsi" : "+a"(a) : "S"(tmp) : "cc", "%rdx");
]])],[has_64bit_asm=yes],[has_64bit_asm=no])
AC_MSG_RESULT([$has_64bit_asm])
])

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