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94 lines
3.8 KiB
94 lines
3.8 KiB
#!/usr/bin/env python3
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# Copyright (c) 2018 The Bitcoin Core developers
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# Distributed under the MIT software license, see the accompanying
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# file COPYING or http://www.opensource.org/licenses/mit-license.php.
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"""Test wallet group functionality."""
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from test_framework.test_framework import BitcoinTestFramework
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from test_framework.messages import CTransaction, FromHex, ToHex
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from test_framework.util import (
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assert_equal,
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)
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def assert_approx(v, vexp, vspan=0.00001):
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if v < vexp - vspan:
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raise AssertionError("%s < [%s..%s]" % (str(v), str(vexp - vspan), str(vexp + vspan)))
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if v > vexp + vspan:
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raise AssertionError("%s > [%s..%s]" % (str(v), str(vexp - vspan), str(vexp + vspan)))
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class WalletGroupTest(BitcoinTestFramework):
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def set_test_params(self):
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self.setup_clean_chain = True
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self.num_nodes = 3
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self.extra_args = [[], [], ['-avoidpartialspends']]
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self.rpc_timewait = 120
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def run_test (self):
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# Mine some coins
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self.nodes[0].generate(110)
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# Get some addresses from the two nodes
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addr1 = [self.nodes[1].getnewaddress() for i in range(3)]
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addr2 = [self.nodes[2].getnewaddress() for i in range(3)]
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addrs = addr1 + addr2
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# Send 1 + 0.5 coin to each address
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[self.nodes[0].sendtoaddress(addr, 1.0) for addr in addrs]
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[self.nodes[0].sendtoaddress(addr, 0.5) for addr in addrs]
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self.nodes[0].generate(1)
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self.sync_all()
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# For each node, send 0.2 coins back to 0;
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# - node[1] should pick one 0.5 UTXO and leave the rest
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# - node[2] should pick one (1.0 + 0.5) UTXO group corresponding to a
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# given address, and leave the rest
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txid1 = self.nodes[1].sendtoaddress(self.nodes[0].getnewaddress(), 0.2)
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tx1 = self.nodes[1].getrawtransaction(txid1, True)
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# txid1 should have 1 input and 2 outputs
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assert_equal(1, len(tx1["vin"]))
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assert_equal(2, len(tx1["vout"]))
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# one output should be 0.2, the other should be ~0.3
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v = [vout["value"] for vout in tx1["vout"]]
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v.sort()
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assert_approx(v[0], 0.2)
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assert_approx(v[1], 0.3, 0.0001)
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txid2 = self.nodes[2].sendtoaddress(self.nodes[0].getnewaddress(), 0.2)
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tx2 = self.nodes[2].getrawtransaction(txid2, True)
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# txid2 should have 2 inputs and 2 outputs
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assert_equal(2, len(tx2["vin"]))
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assert_equal(2, len(tx2["vout"]))
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# one output should be 0.2, the other should be ~1.3
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v = [vout["value"] for vout in tx2["vout"]]
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v.sort()
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assert_approx(v[0], 0.2)
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assert_approx(v[1], 1.3, 0.0001)
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# Empty out node2's wallet
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self.nodes[2].sendtoaddress(address=self.nodes[0].getnewaddress(), amount=self.nodes[2].getbalance(), subtractfeefromamount=True)
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self.sync_all()
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self.nodes[0].generate(1)
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# Fill node2's wallet with 10000 outputs corresponding to the same
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# scriptPubKey
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for i in range(5):
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raw_tx = self.nodes[0].createrawtransaction([{"txid":"0"*64, "vout":0}], [{addr2[0]: 0.05}])
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tx = FromHex(CTransaction(), raw_tx)
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tx.vin = []
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tx.vout = [tx.vout[0]] * 2000
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funded_tx = self.nodes[0].fundrawtransaction(ToHex(tx))
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signed_tx = self.nodes[0].signrawtransactionwithwallet(funded_tx['hex'])
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self.nodes[0].sendrawtransaction(signed_tx['hex'])
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self.nodes[0].generate(1)
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self.sync_all()
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# Check that we can create a transaction that only requires ~100 of our
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# utxos, without pulling in all outputs and creating a transaction that
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# is way too big.
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assert self.nodes[2].sendtoaddress(address=addr2[0], amount=5)
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if __name__ == '__main__':
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WalletGroupTest().main ()
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