Suhas Daftuar
9 years ago
committed by
Alex Morcos
parent
c6c2f0fd78
commit
da6ad5f684
@ -0,0 +1,388 @@
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#!/usr/bin/env python2
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# Copyright (c) 2014-2015 The Bitcoin Core developers
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# Distributed under the MIT software license, see the accompanying
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# file COPYING or http://www.opensource.org/licenses/mit-license.php.
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#
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# Test BIP68 implementation (mempool only)
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#
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from test_framework.test_framework import BitcoinTestFramework
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from test_framework.util import *
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from test_framework.script import *
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from test_framework.mininode import *
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from test_framework.blocktools import *
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COIN = 100000000
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SEQUENCE_LOCKTIME_DISABLE_FLAG = (1<<31)
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SEQUENCE_LOCKTIME_TYPE_FLAG = (1<<22) # this means use time (0 means height)
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SEQUENCE_LOCKTIME_GRANULARITY = 9 # this is a bit-shift
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SEQUENCE_LOCKTIME_MASK = 0x0000ffff
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# RPC error for non-BIP68 final transactions
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NOT_FINAL_ERROR = "64: non-BIP68-final"
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class BIP68Test(BitcoinTestFramework):
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def setup_network(self):
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self.nodes = []
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self.nodes.append(start_node(0, self.options.tmpdir, ["-debug", "-blockprioritysize=0"]))
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self.is_network_split = False
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self.relayfee = self.nodes[0].getnetworkinfo()["relayfee"]
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def run_test(self):
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# Generate some coins
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self.nodes[0].generate(110)
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print "Running test disable flag"
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self.test_disable_flag()
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print "Running test sequence-lock-confirmed-inputs"
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self.test_sequence_lock_confirmed_inputs()
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print "Running test sequence-lock-unconfirmed-inputs"
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self.test_sequence_lock_unconfirmed_inputs()
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# This test needs to change when BIP68 becomes consensus
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print "Running test BIP68 not consensus"
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self.test_bip68_not_consensus()
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print "Passed\n"
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# Test that BIP68 is not in effect if tx version is 1, or if
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# the first sequence bit is set.
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def test_disable_flag(self):
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# Create some unconfirmed inputs
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new_addr = self.nodes[0].getnewaddress()
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self.nodes[0].sendtoaddress(new_addr, 2) # send 2 BTC
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utxos = self.nodes[0].listunspent(0, 0)
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assert(len(utxos) > 0)
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utxo = utxos[0]
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tx1 = CTransaction()
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value = satoshi_round(utxo["amount"] - self.relayfee)*COIN
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# Check that the disable flag disables relative locktime.
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# If sequence locks were used, this would require 1 block for the
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# input to mature.
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sequence_value = SEQUENCE_LOCKTIME_DISABLE_FLAG | 1
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tx1.vin = [CTxIn(COutPoint(int(utxo["txid"], 16), utxo["vout"]), nSequence=sequence_value)]
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tx1.vout = [CTxOut(value, CScript([b'a']))]
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tx1_signed = self.nodes[0].signrawtransaction(ToHex(tx1))["hex"]
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tx1_id = self.nodes[0].sendrawtransaction(tx1_signed)
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tx1_id = int(tx1_id, 16)
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# This transaction will enable sequence-locks, so this transaction should
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# fail
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tx2 = CTransaction()
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tx2.nVersion = 2
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sequence_value = sequence_value & 0x7fffffff
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tx2.vin = [CTxIn(COutPoint(tx1_id, 0), nSequence=sequence_value)]
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tx2.vout = [CTxOut(int(value-self.relayfee*COIN), CScript([b'a']))]
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tx2.rehash()
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try:
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self.nodes[0].sendrawtransaction(ToHex(tx2))
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except JSONRPCException as exp:
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assert_equal(exp.error["message"], NOT_FINAL_ERROR)
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else:
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assert(False)
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# Setting the version back down to 1 should disable the sequence lock,
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# so this should be accepted.
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tx2.nVersion = 1
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self.nodes[0].sendrawtransaction(ToHex(tx2))
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# Calculate the median time past of a prior block ("confirmations" before
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# the current tip).
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def get_median_time_past(self, confirmations):
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block_hash = self.nodes[0].getblockhash(self.nodes[0].getblockcount()-confirmations)
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return self.nodes[0].getblockheader(block_hash)["mediantime"]
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# Test that sequence locks are respected for transactions spending confirmed inputs.
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def test_sequence_lock_confirmed_inputs(self):
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# Create lots of confirmed utxos, and use them to generate lots of random
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# transactions.
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max_outputs = 50
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addresses = []
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while len(addresses) < max_outputs:
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addresses.append(self.nodes[0].getnewaddress())
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while len(self.nodes[0].listunspent()) < 200:
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import random
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random.shuffle(addresses)
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num_outputs = random.randint(1, max_outputs)
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outputs = {}
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for i in xrange(num_outputs):
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outputs[addresses[i]] = random.randint(1, 20)*0.01
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self.nodes[0].sendmany("", outputs)
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self.nodes[0].generate(1)
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utxos = self.nodes[0].listunspent()
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# Try creating a lot of random transactions.
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# Each time, choose a random number of inputs, and randomly set
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# some of those inputs to be sequence locked (and randomly choose
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# between height/time locking). Small random chance of making the locks
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# all pass.
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for i in xrange(400):
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# Randomly choose up to 10 inputs
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num_inputs = random.randint(1, 10)
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random.shuffle(utxos)
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# Track whether any sequence locks used should fail
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should_pass = True
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# Track whether this transaction was built with sequence locks
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using_sequence_locks = False
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tx = CTransaction()
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tx.nVersion = 2
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value = 0
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for j in xrange(num_inputs):
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sequence_value = 0xfffffffe # this disables sequence locks
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# 50% chance we enable sequence locks
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if random.randint(0,1):
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using_sequence_locks = True
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# 10% of the time, make the input sequence value pass
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input_will_pass = (random.randint(1,10) == 1)
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sequence_value = utxos[j]["confirmations"]
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if not input_will_pass:
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sequence_value += 1
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should_pass = False
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# Figure out what the median-time-past was for the confirmed input
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# Note that if an input has N confirmations, we're going back N blocks
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# from the tip so that we're looking up MTP of the block
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# PRIOR to the one the input appears in, as per the BIP68 spec.
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orig_time = self.get_median_time_past(utxos[j]["confirmations"])
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cur_time = self.get_median_time_past(0) # MTP of the tip
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# can only timelock this input if it's not too old -- otherwise use height
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can_time_lock = True
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if ((cur_time - orig_time) >> SEQUENCE_LOCKTIME_GRANULARITY) >= SEQUENCE_LOCKTIME_MASK:
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can_time_lock = False
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# if time-lockable, then 50% chance we make this a time lock
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if random.randint(0,1) and can_time_lock:
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# Find first time-lock value that fails, or latest one that succeeds
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time_delta = sequence_value << SEQUENCE_LOCKTIME_GRANULARITY
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if input_will_pass and time_delta > cur_time - orig_time:
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sequence_value = ((cur_time - orig_time) >> SEQUENCE_LOCKTIME_GRANULARITY)
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elif (not input_will_pass and time_delta <= cur_time - orig_time):
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sequence_value = ((cur_time - orig_time) >> SEQUENCE_LOCKTIME_GRANULARITY)+1
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sequence_value |= SEQUENCE_LOCKTIME_TYPE_FLAG
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tx.vin.append(CTxIn(COutPoint(int(utxos[j]["txid"], 16), utxos[j]["vout"]), nSequence=sequence_value))
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value += utxos[j]["amount"]*COIN
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# Overestimate the size of the tx - signatures should be less than 120 bytes, and leave 50 for the output
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tx_size = len(ToHex(tx))/2 + 120*num_inputs + 50
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tx.vout.append(CTxOut(value-self.relayfee*tx_size*COIN/1000, CScript([b'a'])))
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rawtx = self.nodes[0].signrawtransaction(ToHex(tx))["hex"]
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try:
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self.nodes[0].sendrawtransaction(rawtx)
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except JSONRPCException as exp:
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assert(not should_pass and using_sequence_locks)
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assert_equal(exp.error["message"], NOT_FINAL_ERROR)
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else:
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assert(should_pass or not using_sequence_locks)
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# Recalculate utxos if we successfully sent the transaction
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utxos = self.nodes[0].listunspent()
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# Test that sequence locks on unconfirmed inputs must have nSequence
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# height or time of 0 to be accepted.
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# Then test that BIP68-invalid transactions are removed from the mempool
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# after a reorg.
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def test_sequence_lock_unconfirmed_inputs(self):
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# Store height so we can easily reset the chain at the end of the test
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cur_height = self.nodes[0].getblockcount()
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utxos = self.nodes[0].listunspent()
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# Create a mempool tx.
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txid = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), 2)
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tx1 = FromHex(CTransaction(), self.nodes[0].getrawtransaction(txid))
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tx1.rehash()
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# Anyone-can-spend mempool tx.
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# Sequence lock of 0 should pass.
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tx2 = CTransaction()
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tx2.nVersion = 2
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tx2.vin = [CTxIn(COutPoint(tx1.sha256, 0), nSequence=0)]
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tx2.vout = [CTxOut(int(tx1.vout[0].nValue - self.relayfee*COIN), CScript([b'a']))]
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tx2_raw = self.nodes[0].signrawtransaction(ToHex(tx2))["hex"]
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tx2 = FromHex(tx2, tx2_raw)
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tx2.rehash()
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self.nodes[0].sendrawtransaction(tx2_raw)
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# Create a spend of the 0th output of orig_tx with a sequence lock
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# of 1, and test what happens when submitting.
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# orig_tx.vout[0] must be an anyone-can-spend output
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def test_nonzero_locks(orig_tx, node, relayfee, use_height_lock):
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sequence_value = 1
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if not use_height_lock:
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sequence_value |= SEQUENCE_LOCKTIME_TYPE_FLAG
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tx = CTransaction()
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tx.nVersion = 2
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tx.vin = [CTxIn(COutPoint(orig_tx.sha256, 0), nSequence=sequence_value)]
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tx.vout = [CTxOut(int(orig_tx.vout[0].nValue - relayfee*COIN), CScript([b'a']))]
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tx.rehash()
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try:
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node.sendrawtransaction(ToHex(tx))
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except JSONRPCException as exp:
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assert_equal(exp.error["message"], NOT_FINAL_ERROR)
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assert(orig_tx.hash in node.getrawmempool())
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else:
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# orig_tx must not be in mempool
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assert(orig_tx.hash not in node.getrawmempool())
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return tx
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test_nonzero_locks(tx2, self.nodes[0], self.relayfee, use_height_lock=True)
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test_nonzero_locks(tx2, self.nodes[0], self.relayfee, use_height_lock=False)
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# Now mine some blocks, but make sure tx2 doesn't get mined.
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# Use prioritisetransaction to lower the effective feerate to 0
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self.nodes[0].prioritisetransaction(tx2.hash, -1e15, int(-self.relayfee*COIN))
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cur_time = int(time.time())
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for i in xrange(10):
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self.nodes[0].setmocktime(cur_time + 600)
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self.nodes[0].generate(1)
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cur_time += 600
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assert(tx2.hash in self.nodes[0].getrawmempool())
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test_nonzero_locks(tx2, self.nodes[0], self.relayfee, use_height_lock=True)
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test_nonzero_locks(tx2, self.nodes[0], self.relayfee, use_height_lock=False)
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# Mine tx2, and then try again
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self.nodes[0].prioritisetransaction(tx2.hash, 1e15, int(self.relayfee*COIN))
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# Advance the time on the node so that we can test timelocks
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self.nodes[0].setmocktime(cur_time+600)
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self.nodes[0].generate(1)
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assert(tx2.hash not in self.nodes[0].getrawmempool())
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# Now that tx2 is not in the mempool, a sequence locked spend should
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# succeed
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tx3 = test_nonzero_locks(tx2, self.nodes[0], self.relayfee, use_height_lock=False)
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assert(tx3.hash in self.nodes[0].getrawmempool())
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self.nodes[0].generate(1)
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assert(tx3.hash not in self.nodes[0].getrawmempool())
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# One more test, this time using height locks
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tx4 = test_nonzero_locks(tx3, self.nodes[0], self.relayfee, use_height_lock=True)
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assert(tx4.hash in self.nodes[0].getrawmempool())
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# Now try combining confirmed and unconfirmed inputs
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tx5 = test_nonzero_locks(tx4, self.nodes[0], self.relayfee, use_height_lock=True)
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assert(tx5.hash not in self.nodes[0].getrawmempool())
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tx5.vin.append(CTxIn(COutPoint(int(utxos[0]["txid"], 16), utxos[0]["vout"]), nSequence=1))
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tx5.vout[0].nValue += int(utxos[0]["amount"]*COIN)
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raw_tx5 = self.nodes[0].signrawtransaction(ToHex(tx5))["hex"]
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try:
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self.nodes[0].sendrawtransaction(raw_tx5)
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except JSONRPCException as exp:
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assert_equal(exp.error["message"], NOT_FINAL_ERROR)
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else:
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assert(False)
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# Test mempool-BIP68 consistency after reorg
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#
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# State of the transactions in the last blocks:
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# ... -> [ tx2 ] -> [ tx3 ]
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# tip-1 tip
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# And currently tx4 is in the mempool.
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#
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# If we invalidate the tip, tx3 should get added to the mempool, causing
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# tx4 to be removed (fails sequence-lock).
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self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
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assert(tx4.hash not in self.nodes[0].getrawmempool())
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assert(tx3.hash in self.nodes[0].getrawmempool())
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# Now mine 2 empty blocks to reorg out the current tip (labeled tip-1 in
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# diagram above).
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# This would cause tx2 to be added back to the mempool, which in turn causes
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# tx3 to be removed.
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tip = int(self.nodes[0].getblockhash(self.nodes[0].getblockcount()-1), 16)
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height = self.nodes[0].getblockcount()
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for i in xrange(2):
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block = create_block(tip, create_coinbase(height), cur_time)
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block.nVersion = 3
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block.rehash()
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block.solve()
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tip = block.sha256
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height += 1
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self.nodes[0].submitblock(ToHex(block))
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cur_time += 1
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mempool = self.nodes[0].getrawmempool()
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assert(tx3.hash not in mempool)
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assert(tx2.hash in mempool)
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# Reset the chain and get rid of the mocktimed-blocks
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self.nodes[0].setmocktime(0)
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self.nodes[0].invalidateblock(self.nodes[0].getblockhash(cur_height+1))
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self.nodes[0].generate(10)
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# Make sure that BIP68 isn't being used to validate blocks.
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def test_bip68_not_consensus(self):
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txid = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), 2)
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tx1 = FromHex(CTransaction(), self.nodes[0].getrawtransaction(txid))
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tx1.rehash()
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# Make an anyone-can-spend transaction
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tx2 = CTransaction()
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tx2.nVersion = 1
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tx2.vin = [CTxIn(COutPoint(tx1.sha256, 0), nSequence=0)]
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tx2.vout = [CTxOut(int(tx1.vout[0].nValue - self.relayfee*COIN), CScript([b'a']))]
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# sign tx2
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tx2_raw = self.nodes[0].signrawtransaction(ToHex(tx2))["hex"]
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tx2 = FromHex(tx2, tx2_raw)
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tx2.rehash()
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self.nodes[0].sendrawtransaction(ToHex(tx2))
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# Now make an invalid spend of tx2 according to BIP68
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sequence_value = 100 # 100 block relative locktime
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tx3 = CTransaction()
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tx3.nVersion = 2
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tx3.vin = [CTxIn(COutPoint(tx2.sha256, 0), nSequence=sequence_value)]
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tx3.vout = [CTxOut(int(tx2.vout[0].nValue - self.relayfee*COIN), CScript([b'a']))]
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tx3.rehash()
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try:
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self.nodes[0].sendrawtransaction(ToHex(tx3))
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except JSONRPCException as exp:
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assert_equal(exp.error["message"], NOT_FINAL_ERROR)
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else:
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assert(False)
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# make a block that violates bip68; ensure that the tip updates
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tip = int(self.nodes[0].getbestblockhash(), 16)
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block = create_block(tip, create_coinbase(self.nodes[0].getblockcount()+1))
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block.nVersion = 3
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block.vtx.extend([tx1, tx2, tx3])
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block.hashMerkleRoot = block.calc_merkle_root()
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block.rehash()
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block.solve()
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self.nodes[0].submitblock(ToHex(block))
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assert_equal(self.nodes[0].getbestblockhash(), block.hash)
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if __name__ == '__main__':
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BIP68Test().main()
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