Add test showing bug in mempool packages

pull/262/head
Suhas Daftuar 9 years ago committed by Suhas Daftuar
parent 999c8be81a
commit 598b25d5ee

@ -15,22 +15,24 @@ class MempoolPackagesTest(BitcoinTestFramework):
def setup_network(self):
self.nodes = []
self.nodes.append(start_node(0, self.options.tmpdir, ["-maxorphantx=1000", "-relaypriority=0"]))
self.nodes.append(start_node(0, self.options.tmpdir, ["-maxorphantx=1000", "-relaypriority=0", "-debug"]))
self.nodes.append(start_node(1, self.options.tmpdir, ["-maxorphantx=1000", "-relaypriority=0", "-limitancestorcount=5", "-debug"]))
connect_nodes(self.nodes[0], 1)
self.is_network_split = False
self.sync_all()
# Build a transaction that spends parent_txid:vout
# Return amount sent
def chain_transaction(self, parent_txid, vout, value, fee, num_outputs):
def chain_transaction(self, node, parent_txid, vout, value, fee, num_outputs):
send_value = satoshi_round((value - fee)/num_outputs)
inputs = [ {'txid' : parent_txid, 'vout' : vout} ]
outputs = {}
for i in xrange(num_outputs):
outputs[self.nodes[0].getnewaddress()] = send_value
rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
signedtx = self.nodes[0].signrawtransaction(rawtx)
txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
fulltx = self.nodes[0].getrawtransaction(txid, 1)
outputs[node.getnewaddress()] = send_value
rawtx = node.createrawtransaction(inputs, outputs)
signedtx = node.signrawtransaction(rawtx)
txid = node.sendrawtransaction(signedtx['hex'])
fulltx = node.getrawtransaction(txid, 1)
assert(len(fulltx['vout']) == num_outputs) # make sure we didn't generate a change output
return (txid, send_value)
@ -46,7 +48,7 @@ class MempoolPackagesTest(BitcoinTestFramework):
# 100 transactions off a confirmed tx should be fine
chain = []
for i in xrange(100):
(txid, sent_value) = self.chain_transaction(txid, 0, value, fee, 1)
(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, 0, value, fee, 1)
value = sent_value
chain.append(txid)
@ -69,10 +71,12 @@ class MempoolPackagesTest(BitcoinTestFramework):
# Adding one more transaction on to the chain should fail.
try:
self.chain_transaction(txid, vout, value, fee, 1)
self.chain_transaction(self.nodes[0], txid, vout, value, fee, 1)
except JSONRPCException as e:
print "too-long-ancestor-chain successfully rejected"
# TODO: check that node1's mempool is as expected
# TODO: test ancestor size limits
# Now test descendant chain limits
@ -82,7 +86,7 @@ class MempoolPackagesTest(BitcoinTestFramework):
transaction_package = []
# First create one parent tx with 10 children
(txid, sent_value) = self.chain_transaction(txid, vout, value, fee, 10)
(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, vout, value, fee, 10)
parent_transaction = txid
for i in xrange(10):
transaction_package.append({'txid': txid, 'vout': i, 'amount': sent_value})
@ -90,7 +94,7 @@ class MempoolPackagesTest(BitcoinTestFramework):
for i in xrange(1000):
utxo = transaction_package.pop(0)
try:
(txid, sent_value) = self.chain_transaction(utxo['txid'], utxo['vout'], utxo['amount'], fee, 10)
(txid, sent_value) = self.chain_transaction(self.nodes[0], utxo['txid'], utxo['vout'], utxo['amount'], fee, 10)
for j in xrange(10):
transaction_package.append({'txid': txid, 'vout': j, 'amount': sent_value})
if i == 998:
@ -101,7 +105,74 @@ class MempoolPackagesTest(BitcoinTestFramework):
assert_equal(i, 999)
print "tx that would create too large descendant package successfully rejected"
# TODO: check that node1's mempool is as expected
# TODO: test descendant size limits
# Test reorg handling
# First, the basics:
self.nodes[0].generate(1)
sync_blocks(self.nodes)
self.nodes[1].invalidateblock(self.nodes[0].getbestblockhash())
self.nodes[1].reconsiderblock(self.nodes[0].getbestblockhash())
# Now test the case where node1 has a transaction T in its mempool that
# depends on transactions A and B which are in a mined block, and the
# block containing A and B is disconnected, AND B is not accepted back
# into node1's mempool because its ancestor count is too high.
# Create 8 transactions, like so:
# Tx0 -> Tx1 (vout0)
# \--> Tx2 (vout1) -> Tx3 -> Tx4 -> Tx5 -> Tx6 -> Tx7
#
# Mine them in the next block, then generate a new tx8 that spends
# Tx1 and Tx7, and add to node1's mempool, then disconnect the
# last block.
# Create tx0 with 2 outputs
utxo = self.nodes[0].listunspent()
txid = utxo[0]['txid']
value = utxo[0]['amount']
vout = utxo[0]['vout']
send_value = satoshi_round((value - fee)/2)
inputs = [ {'txid' : txid, 'vout' : vout} ]
outputs = {}
for i in xrange(2):
outputs[self.nodes[0].getnewaddress()] = send_value
rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
signedtx = self.nodes[0].signrawtransaction(rawtx)
txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
tx0_id = txid
value = send_value
# Create tx1
(tx1_id, tx1_value) = self.chain_transaction(self.nodes[0], tx0_id, 0, value, fee, 1)
# Create tx2-7
vout = 1
txid = tx0_id
for i in xrange(6):
(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, vout, value, fee, 1)
vout = 0
value = sent_value
# Mine these in a block
self.nodes[0].generate(1)
self.sync_all()
# Now generate tx8, with a big fee
inputs = [ {'txid' : tx1_id, 'vout': 0}, {'txid' : txid, 'vout': 0} ]
outputs = { self.nodes[0].getnewaddress() : send_value + value - 4*fee }
rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
signedtx = self.nodes[0].signrawtransaction(rawtx)
txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
sync_mempools(self.nodes)
# Now try to disconnect the tip on each node...
self.nodes[1].invalidateblock(self.nodes[1].getbestblockhash())
self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
sync_blocks(self.nodes)
if __name__ == '__main__':
MempoolPackagesTest().main()

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