|
|
|
#!/usr/bin/env python3
|
|
|
|
# Copyright (c) 2014-2020 The Bitcoin Core developers
|
|
|
|
# Distributed under the MIT software license, see the accompanying
|
|
|
|
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
|
|
|
|
"""Test mempool re-org scenarios.
|
|
|
|
|
|
|
|
Test re-org scenarios with a mempool that contains transactions
|
|
|
|
that spend (directly or indirectly) coinbase transactions.
|
|
|
|
"""
|
|
|
|
|
|
|
|
from test_framework.blocktools import create_raw_transaction
|
|
|
|
from test_framework.test_framework import BitcoinTestFramework
|
|
|
|
from test_framework.util import assert_equal, assert_raises_rpc_error
|
|
|
|
|
|
|
|
|
|
|
|
class MempoolCoinbaseTest(BitcoinTestFramework):
|
|
|
|
def set_test_params(self):
|
|
|
|
self.num_nodes = 2
|
|
|
|
self.extra_args = [
|
|
|
|
[
|
|
|
|
'-whitelist=noban@127.0.0.1', # immediate tx relay
|
|
|
|
],
|
|
|
|
[]
|
|
|
|
]
|
|
|
|
|
|
|
|
def skip_test_if_missing_module(self):
|
|
|
|
self.skip_if_no_wallet()
|
|
|
|
|
|
|
|
def run_test(self):
|
|
|
|
# Start with a 200 block chain
|
|
|
|
assert_equal(self.nodes[0].getblockcount(), 200)
|
|
|
|
|
|
|
|
# Mine four blocks. After this, nodes[0] blocks
|
|
|
|
# 101, 102, and 103 are spend-able.
|
|
|
|
new_blocks = self.nodes[1].generate(4)
|
|
|
|
self.sync_all()
|
|
|
|
|
|
|
|
node0_address = self.nodes[0].getnewaddress()
|
|
|
|
node1_address = self.nodes[1].getnewaddress()
|
|
|
|
|
|
|
|
# Three scenarios for re-orging coinbase spends in the memory pool:
|
|
|
|
# 1. Direct coinbase spend : spend_101
|
|
|
|
# 2. Indirect (coinbase spend in chain, child in mempool) : spend_102 and spend_102_1
|
|
|
|
# 3. Indirect (coinbase and child both in chain) : spend_103 and spend_103_1
|
|
|
|
# Use invalidatblock to make all of the above coinbase spends invalid (immature coinbase),
|
|
|
|
# and make sure the mempool code behaves correctly.
|
|
|
|
b = [self.nodes[0].getblockhash(n) for n in range(101, 105)]
|
|
|
|
coinbase_txids = [self.nodes[0].getblock(h)['tx'][0] for h in b]
|
|
|
|
spend_101_raw = create_raw_transaction(self.nodes[0], coinbase_txids[1], node1_address, amount=49.99)
|
|
|
|
spend_102_raw = create_raw_transaction(self.nodes[0], coinbase_txids[2], node0_address, amount=49.99)
|
|
|
|
spend_103_raw = create_raw_transaction(self.nodes[0], coinbase_txids[3], node0_address, amount=49.99)
|
|
|
|
|
|
|
|
# Create a transaction which is time-locked to two blocks in the future
|
|
|
|
timelock_tx = self.nodes[0].createrawtransaction(
|
|
|
|
inputs=[{
|
|
|
|
"txid": coinbase_txids[0],
|
|
|
|
"vout": 0,
|
|
|
|
}],
|
|
|
|
outputs={node0_address: 49.99},
|
|
|
|
locktime=self.nodes[0].getblockcount() + 2,
|
|
|
|
)
|
|
|
|
timelock_tx = self.nodes[0].signrawtransactionwithwallet(timelock_tx)["hex"]
|
|
|
|
# This will raise an exception because the timelock transaction is too immature to spend
|
|
|
|
assert_raises_rpc_error(-26, "non-final", self.nodes[0].sendrawtransaction, timelock_tx)
|
|
|
|
|
|
|
|
# Broadcast and mine spend_102 and 103:
|
|
|
|
spend_102_id = self.nodes[0].sendrawtransaction(spend_102_raw)
|
|
|
|
spend_103_id = self.nodes[0].sendrawtransaction(spend_103_raw)
|
|
|
|
self.nodes[0].generate(1)
|
|
|
|
# Time-locked transaction is still too immature to spend
|
|
|
|
assert_raises_rpc_error(-26, 'non-final', self.nodes[0].sendrawtransaction, timelock_tx)
|
|
|
|
|
|
|
|
# Create 102_1 and 103_1:
|
|
|
|
spend_102_1_raw = create_raw_transaction(self.nodes[0], spend_102_id, node1_address, amount=49.98)
|
|
|
|
spend_103_1_raw = create_raw_transaction(self.nodes[0], spend_103_id, node1_address, amount=49.98)
|
|
|
|
|
|
|
|
# Broadcast and mine 103_1:
|
|
|
|
spend_103_1_id = self.nodes[0].sendrawtransaction(spend_103_1_raw)
|
|
|
|
last_block = self.nodes[0].generate(1)
|
|
|
|
# Sync blocks, so that peer 1 gets the block before timelock_tx
|
|
|
|
# Otherwise, peer 1 would put the timelock_tx in recentRejects
|
|
|
|
self.sync_all()
|
|
|
|
|
|
|
|
# Time-locked transaction can now be spent
|
|
|
|
timelock_tx_id = self.nodes[0].sendrawtransaction(timelock_tx)
|
|
|
|
|
|
|
|
# ... now put spend_101 and spend_102_1 in memory pools:
|
|
|
|
spend_101_id = self.nodes[0].sendrawtransaction(spend_101_raw)
|
|
|
|
spend_102_1_id = self.nodes[0].sendrawtransaction(spend_102_1_raw)
|
|
|
|
|
|
|
|
assert_equal(set(self.nodes[0].getrawmempool()), {spend_101_id, spend_102_1_id, timelock_tx_id})
|
|
|
|
self.sync_all()
|
|
|
|
|
|
|
|
for node in self.nodes:
|
|
|
|
node.invalidateblock(last_block[0])
|
|
|
|
# Time-locked transaction is now too immature and has been removed from the mempool
|
|
|
|
# spend_103_1 has been re-orged out of the chain and is back in the mempool
|
|
|
|
assert_equal(set(self.nodes[0].getrawmempool()), {spend_101_id, spend_102_1_id, spend_103_1_id})
|
|
|
|
|
|
|
|
# Use invalidateblock to re-org back and make all those coinbase spends
|
|
|
|
# immature/invalid:
|
|
|
|
for node in self.nodes:
|
|
|
|
node.invalidateblock(new_blocks[0])
|
|
|
|
|
|
|
|
# mempool should be empty.
|
|
|
|
assert_equal(set(self.nodes[0].getrawmempool()), set())
|
|
|
|
self.sync_all()
|
|
|
|
|
|
|
|
|
|
|
|
if __name__ == '__main__':
|
|
|
|
MempoolCoinbaseTest().main()
|