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252 lines
10 KiB
252 lines
10 KiB
#!/usr/bin/env python3
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# Copyright (c) 2014-2016 The Bitcoin Core developers
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# Distributed under the MIT software license, see the accompanying
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# file COPYING or http://www.opensource.org/licenses/mit-license.php.
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"""Test descendant package tracking code."""
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from test_framework.test_framework import BitcoinTestFramework
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from test_framework.util import *
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from test_framework.mininode import COIN
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MAX_ANCESTORS = 25
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MAX_DESCENDANTS = 25
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class MempoolPackagesTest(BitcoinTestFramework):
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def __init__(self):
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super().__init__()
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self.num_nodes = 2
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self.setup_clean_chain = False
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def setup_network(self):
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self.nodes = []
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self.nodes.append(start_node(0, self.options.tmpdir, ["-maxorphantx=1000"]))
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self.nodes.append(start_node(1, self.options.tmpdir, ["-maxorphantx=1000", "-limitancestorcount=5"]))
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connect_nodes(self.nodes[0], 1)
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self.is_network_split = False
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self.sync_all()
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# Build a transaction that spends parent_txid:vout
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# Return amount sent
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def chain_transaction(self, node, parent_txid, vout, value, fee, num_outputs):
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send_value = satoshi_round((value - fee)/num_outputs)
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inputs = [ {'txid' : parent_txid, 'vout' : vout} ]
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outputs = {}
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for i in range(num_outputs):
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outputs[node.getnewaddress()] = send_value
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rawtx = node.createrawtransaction(inputs, outputs)
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signedtx = node.signrawtransaction(rawtx)
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txid = node.sendrawtransaction(signedtx['hex'])
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fulltx = node.getrawtransaction(txid, 1)
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assert(len(fulltx['vout']) == num_outputs) # make sure we didn't generate a change output
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return (txid, send_value)
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def run_test(self):
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''' Mine some blocks and have them mature. '''
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self.nodes[0].generate(101)
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utxo = self.nodes[0].listunspent(10)
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txid = utxo[0]['txid']
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vout = utxo[0]['vout']
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value = utxo[0]['amount']
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fee = Decimal("0.0001")
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# MAX_ANCESTORS transactions off a confirmed tx should be fine
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chain = []
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for i in range(MAX_ANCESTORS):
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(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, 0, value, fee, 1)
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value = sent_value
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chain.append(txid)
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# Check mempool has MAX_ANCESTORS transactions in it, and descendant
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# count and fees should look correct
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mempool = self.nodes[0].getrawmempool(True)
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assert_equal(len(mempool), MAX_ANCESTORS)
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descendant_count = 1
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descendant_fees = 0
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descendant_size = 0
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descendants = []
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ancestors = list(chain)
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for x in reversed(chain):
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# Check that getmempoolentry is consistent with getrawmempool
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entry = self.nodes[0].getmempoolentry(x)
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assert_equal(entry, mempool[x])
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# Check that the descendant calculations are correct
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assert_equal(mempool[x]['descendantcount'], descendant_count)
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descendant_fees += mempool[x]['fee']
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assert_equal(mempool[x]['modifiedfee'], mempool[x]['fee'])
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assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN)
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descendant_size += mempool[x]['size']
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assert_equal(mempool[x]['descendantsize'], descendant_size)
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descendant_count += 1
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# Check that getmempooldescendants is correct
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assert_equal(sorted(descendants), sorted(self.nodes[0].getmempooldescendants(x)))
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descendants.append(x)
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# Check that getmempoolancestors is correct
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ancestors.remove(x)
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assert_equal(sorted(ancestors), sorted(self.nodes[0].getmempoolancestors(x)))
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# Check that getmempoolancestors/getmempooldescendants correctly handle verbose=true
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v_ancestors = self.nodes[0].getmempoolancestors(chain[-1], True)
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assert_equal(len(v_ancestors), len(chain)-1)
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for x in v_ancestors.keys():
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assert_equal(mempool[x], v_ancestors[x])
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assert(chain[-1] not in v_ancestors.keys())
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v_descendants = self.nodes[0].getmempooldescendants(chain[0], True)
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assert_equal(len(v_descendants), len(chain)-1)
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for x in v_descendants.keys():
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assert_equal(mempool[x], v_descendants[x])
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assert(chain[0] not in v_descendants.keys())
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# Check that ancestor modified fees includes fee deltas from
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# prioritisetransaction
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self.nodes[0].prioritisetransaction(chain[0], 1000)
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mempool = self.nodes[0].getrawmempool(True)
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ancestor_fees = 0
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for x in chain:
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ancestor_fees += mempool[x]['fee']
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assert_equal(mempool[x]['ancestorfees'], ancestor_fees * COIN + 1000)
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# Undo the prioritisetransaction for later tests
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self.nodes[0].prioritisetransaction(chain[0], -1000)
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# Check that descendant modified fees includes fee deltas from
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# prioritisetransaction
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self.nodes[0].prioritisetransaction(chain[-1], 1000)
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mempool = self.nodes[0].getrawmempool(True)
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descendant_fees = 0
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for x in reversed(chain):
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descendant_fees += mempool[x]['fee']
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assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN + 1000)
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# Adding one more transaction on to the chain should fail.
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assert_raises_jsonrpc(-26, "too-long-mempool-chain", self.chain_transaction, self.nodes[0], txid, vout, value, fee, 1)
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# Check that prioritising a tx before it's added to the mempool works
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# First clear the mempool by mining a block.
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self.nodes[0].generate(1)
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sync_blocks(self.nodes)
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assert_equal(len(self.nodes[0].getrawmempool()), 0)
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# Prioritise a transaction that has been mined, then add it back to the
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# mempool by using invalidateblock.
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self.nodes[0].prioritisetransaction(chain[-1], 2000)
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self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
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# Keep node1's tip synced with node0
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self.nodes[1].invalidateblock(self.nodes[1].getbestblockhash())
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# Now check that the transaction is in the mempool, with the right modified fee
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mempool = self.nodes[0].getrawmempool(True)
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descendant_fees = 0
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for x in reversed(chain):
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descendant_fees += mempool[x]['fee']
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if (x == chain[-1]):
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assert_equal(mempool[x]['modifiedfee'], mempool[x]['fee']+satoshi_round(0.00002))
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assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN + 2000)
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# TODO: check that node1's mempool is as expected
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# TODO: test ancestor size limits
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# Now test descendant chain limits
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txid = utxo[1]['txid']
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value = utxo[1]['amount']
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vout = utxo[1]['vout']
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transaction_package = []
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# First create one parent tx with 10 children
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(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, vout, value, fee, 10)
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parent_transaction = txid
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for i in range(10):
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transaction_package.append({'txid': txid, 'vout': i, 'amount': sent_value})
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# Sign and send up to MAX_DESCENDANT transactions chained off the parent tx
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for i in range(MAX_DESCENDANTS - 1):
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utxo = transaction_package.pop(0)
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(txid, sent_value) = self.chain_transaction(self.nodes[0], utxo['txid'], utxo['vout'], utxo['amount'], fee, 10)
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for j in range(10):
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transaction_package.append({'txid': txid, 'vout': j, 'amount': sent_value})
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mempool = self.nodes[0].getrawmempool(True)
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assert_equal(mempool[parent_transaction]['descendantcount'], MAX_DESCENDANTS)
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# Sending one more chained transaction will fail
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utxo = transaction_package.pop(0)
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assert_raises_jsonrpc(-26, "too-long-mempool-chain", self.chain_transaction, self.nodes[0], utxo['txid'], utxo['vout'], utxo['amount'], fee, 10)
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# TODO: check that node1's mempool is as expected
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# TODO: test descendant size limits
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# Test reorg handling
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# First, the basics:
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self.nodes[0].generate(1)
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sync_blocks(self.nodes)
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self.nodes[1].invalidateblock(self.nodes[0].getbestblockhash())
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self.nodes[1].reconsiderblock(self.nodes[0].getbestblockhash())
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# Now test the case where node1 has a transaction T in its mempool that
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# depends on transactions A and B which are in a mined block, and the
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# block containing A and B is disconnected, AND B is not accepted back
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# into node1's mempool because its ancestor count is too high.
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# Create 8 transactions, like so:
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# Tx0 -> Tx1 (vout0)
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# \--> Tx2 (vout1) -> Tx3 -> Tx4 -> Tx5 -> Tx6 -> Tx7
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#
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# Mine them in the next block, then generate a new tx8 that spends
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# Tx1 and Tx7, and add to node1's mempool, then disconnect the
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# last block.
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# Create tx0 with 2 outputs
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utxo = self.nodes[0].listunspent()
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txid = utxo[0]['txid']
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value = utxo[0]['amount']
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vout = utxo[0]['vout']
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send_value = satoshi_round((value - fee)/2)
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inputs = [ {'txid' : txid, 'vout' : vout} ]
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outputs = {}
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for i in range(2):
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outputs[self.nodes[0].getnewaddress()] = send_value
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rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
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signedtx = self.nodes[0].signrawtransaction(rawtx)
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txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
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tx0_id = txid
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value = send_value
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# Create tx1
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(tx1_id, tx1_value) = self.chain_transaction(self.nodes[0], tx0_id, 0, value, fee, 1)
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# Create tx2-7
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vout = 1
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txid = tx0_id
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for i in range(6):
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(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, vout, value, fee, 1)
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vout = 0
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value = sent_value
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# Mine these in a block
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self.nodes[0].generate(1)
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self.sync_all()
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# Now generate tx8, with a big fee
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inputs = [ {'txid' : tx1_id, 'vout': 0}, {'txid' : txid, 'vout': 0} ]
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outputs = { self.nodes[0].getnewaddress() : send_value + value - 4*fee }
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rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
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signedtx = self.nodes[0].signrawtransaction(rawtx)
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txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
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sync_mempools(self.nodes)
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# Now try to disconnect the tip on each node...
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self.nodes[1].invalidateblock(self.nodes[1].getbestblockhash())
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self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
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sync_blocks(self.nodes)
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if __name__ == '__main__':
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MempoolPackagesTest().main()
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