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#!/usr/bin/env python3
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# Copyright (c) 2014-2022 The Bitcoin Core developers
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# Distributed under the MIT software license, see the accompanying
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# file COPYING or http://www.opensource.org/licenses/mit-license.php.
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"""Test the RBF code."""
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from decimal import Decimal
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from test_framework.messages import (
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MAX_BIP125_RBF_SEQUENCE,
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COIN,
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SEQUENCE_FINAL,
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)
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from test_framework.test_framework import BitcoinTestFramework
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from test_framework.util import (
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assert_equal,
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assert_raises_rpc_error,
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)
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from test_framework.wallet import MiniWallet
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from test_framework.address import ADDRESS_BCRT1_UNSPENDABLE
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MAX_REPLACEMENT_LIMIT = 100
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class ReplaceByFeeTest(BitcoinTestFramework):
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def add_options(self, parser):
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self.add_wallet_options(parser)
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def set_test_params(self):
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self.num_nodes = 2
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# both nodes disable full-rbf to test BIP125 signaling
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self.extra_args = [
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[
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"-mempoolfullrbf=0",
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"-limitancestorcount=50",
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"-limitancestorsize=101",
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"-limitdescendantcount=200",
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"-limitdescendantsize=101",
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],
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# second node has default mempool parameters, besides mempoolfullrbf being disabled
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[
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"-mempoolfullrbf=0",
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],
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]
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self.supports_cli = False
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def run_test(self):
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self.wallet = MiniWallet(self.nodes[0])
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self.log.info("Running test simple doublespend...")
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self.test_simple_doublespend()
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self.log.info("Running test doublespend chain...")
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self.test_doublespend_chain()
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self.log.info("Running test doublespend tree...")
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self.test_doublespend_tree()
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self.log.info("Running test replacement feeperkb...")
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self.test_replacement_feeperkb()
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self.log.info("Running test spends of conflicting outputs...")
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self.test_spends_of_conflicting_outputs()
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self.log.info("Running test new unconfirmed inputs...")
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self.test_new_unconfirmed_inputs()
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self.log.info("Running test too many replacements...")
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self.test_too_many_replacements()
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self.log.info("Running test too many replacements using default mempool params...")
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self.test_too_many_replacements_with_default_mempool_params()
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self.log.info("Running test opt-in...")
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self.test_opt_in()
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self.log.info("Running test RPC...")
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self.test_rpc()
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self.log.info("Running test prioritised transactions...")
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self.test_prioritised_transactions()
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self.log.info("Running test no inherited signaling...")
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self.test_no_inherited_signaling()
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self.log.info("Running test replacement relay fee...")
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self.test_replacement_relay_fee()
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self.log.info("Running test full replace by fee...")
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self.test_fullrbf()
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self.log.info("Passed")
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def make_utxo(self, node, amount, *, confirmed=True, scriptPubKey=None):
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"""Create a txout with a given amount and scriptPubKey
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confirmed - txout created will be confirmed in the blockchain;
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unconfirmed otherwise.
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"""
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tx = self.wallet.send_to(from_node=node, scriptPubKey=scriptPubKey or self.wallet.get_scriptPubKey(), amount=amount)
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if confirmed:
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mempool_size = len(node.getrawmempool())
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while mempool_size > 0:
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self.generate(node, 1)
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new_size = len(node.getrawmempool())
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# Error out if we have something stuck in the mempool, as this
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# would likely be a bug.
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assert new_size < mempool_size
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mempool_size = new_size
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return self.wallet.get_utxo(txid=tx["txid"], vout=tx["sent_vout"])
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def test_simple_doublespend(self):
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"""Simple doublespend"""
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# we use MiniWallet to create a transaction template with inputs correctly set,
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# and modify the output (amount, scriptPubKey) according to our needs
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tx = self.wallet.create_self_transfer()["tx"]
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tx1a_txid = self.nodes[0].sendrawtransaction(tx.serialize().hex())
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# Should fail because we haven't changed the fee
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tx.vout[0].scriptPubKey[-1] ^= 1
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# This will raise an exception due to insufficient fee
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assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx.serialize().hex(), 0)
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# Extra 0.1 BTC fee
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tx.vout[0].nValue -= int(0.1 * COIN)
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tx1b_hex = tx.serialize().hex()
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# Works when enabled
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tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, 0)
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mempool = self.nodes[0].getrawmempool()
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assert tx1a_txid not in mempool
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assert tx1b_txid in mempool
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assert_equal(tx1b_hex, self.nodes[0].getrawtransaction(tx1b_txid))
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def test_doublespend_chain(self):
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"""Doublespend of a long chain"""
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initial_nValue = 5 * COIN
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tx0_outpoint = self.make_utxo(self.nodes[0], initial_nValue)
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prevout = tx0_outpoint
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remaining_value = initial_nValue
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chain_txids = []
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while remaining_value > 1 * COIN:
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remaining_value -= int(0.1 * COIN)
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prevout = self.wallet.send_self_transfer(
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from_node=self.nodes[0],
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utxo_to_spend=prevout,
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sequence=0,
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fee=Decimal("0.1"),
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)["new_utxo"]
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chain_txids.append(prevout["txid"])
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# Whether the double-spend is allowed is evaluated by including all
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# child fees - 4 BTC - so this attempt is rejected.
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dbl_tx = self.wallet.create_self_transfer(
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utxo_to_spend=tx0_outpoint,
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sequence=0,
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fee=Decimal("3"),
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)["tx"]
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dbl_tx_hex = dbl_tx.serialize().hex()
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# This will raise an exception due to insufficient fee
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assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, 0)
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# Accepted with sufficient fee
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dbl_tx.vout[0].nValue = int(0.1 * COIN)
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dbl_tx_hex = dbl_tx.serialize().hex()
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self.nodes[0].sendrawtransaction(dbl_tx_hex, 0)
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mempool = self.nodes[0].getrawmempool()
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for doublespent_txid in chain_txids:
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assert doublespent_txid not in mempool
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def test_doublespend_tree(self):
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"""Doublespend of a big tree of transactions"""
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initial_nValue = 5 * COIN
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tx0_outpoint = self.make_utxo(self.nodes[0], initial_nValue)
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def branch(prevout, initial_value, max_txs, tree_width=5, fee=0.00001 * COIN, _total_txs=None):
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if _total_txs is None:
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_total_txs = [0]
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if _total_txs[0] >= max_txs:
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return
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txout_value = (initial_value - fee) // tree_width
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if txout_value < fee:
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return
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tx = self.wallet.send_self_transfer_multi(
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utxos_to_spend=[prevout],
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from_node=self.nodes[0],
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sequence=0,
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num_outputs=tree_width,
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amount_per_output=txout_value,
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)
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yield tx["txid"]
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_total_txs[0] += 1
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for utxo in tx["new_utxos"]:
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for x in branch(utxo, txout_value,
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max_txs,
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tree_width=tree_width, fee=fee,
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_total_txs=_total_txs):
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yield x
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fee = int(0.00001 * COIN)
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n = MAX_REPLACEMENT_LIMIT
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tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
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assert_equal(len(tree_txs), n)
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# Attempt double-spend, will fail because too little fee paid
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dbl_tx_hex = self.wallet.create_self_transfer(
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utxo_to_spend=tx0_outpoint,
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sequence=0,
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fee=(Decimal(fee) / COIN) * n,
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)["hex"]
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# This will raise an exception due to insufficient fee
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assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, 0)
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# 0.1 BTC fee is enough
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dbl_tx_hex = self.wallet.create_self_transfer(
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utxo_to_spend=tx0_outpoint,
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sequence=0,
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fee=(Decimal(fee) / COIN) * n + Decimal("0.1"),
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)["hex"]
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self.nodes[0].sendrawtransaction(dbl_tx_hex, 0)
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mempool = self.nodes[0].getrawmempool()
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for txid in tree_txs:
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assert txid not in mempool
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# Try again, but with more total transactions than the "max txs
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# double-spent at once" anti-DoS limit.
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for n in (MAX_REPLACEMENT_LIMIT + 1, MAX_REPLACEMENT_LIMIT * 2):
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fee = int(0.00001 * COIN)
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tx0_outpoint = self.make_utxo(self.nodes[0], initial_nValue)
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tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
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assert_equal(len(tree_txs), n)
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dbl_tx_hex = self.wallet.create_self_transfer(
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utxo_to_spend=tx0_outpoint,
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sequence=0,
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fee=2 * (Decimal(fee) / COIN) * n,
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)["hex"]
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# This will raise an exception
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assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, dbl_tx_hex, 0)
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for txid in tree_txs:
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self.nodes[0].getrawtransaction(txid)
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def test_replacement_feeperkb(self):
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"""Replacement requires fee-per-KB to be higher"""
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tx0_outpoint = self.make_utxo(self.nodes[0], int(1.1 * COIN))
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self.wallet.send_self_transfer(
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from_node=self.nodes[0],
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utxo_to_spend=tx0_outpoint,
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sequence=0,
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fee=Decimal("0.1"),
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)
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# Higher fee, but the fee per KB is much lower, so the replacement is
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# rejected.
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tx1b_hex = self.wallet.create_self_transfer_multi(
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utxos_to_spend=[tx0_outpoint],
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sequence=0,
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num_outputs=100,
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amount_per_output=1000,
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)["hex"]
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# This will raise an exception due to insufficient fee
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assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, 0)
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def test_spends_of_conflicting_outputs(self):
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"""Replacements that spend conflicting tx outputs are rejected"""
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utxo1 = self.make_utxo(self.nodes[0], int(1.2 * COIN))
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utxo2 = self.make_utxo(self.nodes[0], 3 * COIN)
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tx1a_utxo = self.wallet.send_self_transfer(
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from_node=self.nodes[0],
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utxo_to_spend=utxo1,
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sequence=0,
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fee=Decimal("0.1"),
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)["new_utxo"]
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# Direct spend an output of the transaction we're replacing.
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tx2_hex = self.wallet.create_self_transfer_multi(
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utxos_to_spend=[utxo1, utxo2, tx1a_utxo],
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sequence=0,
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amount_per_output=int(COIN * tx1a_utxo["value"]),
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)["hex"]
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# This will raise an exception
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assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, 0)
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# Spend tx1a's output to test the indirect case.
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tx1b_utxo = self.wallet.send_self_transfer(
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from_node=self.nodes[0],
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utxo_to_spend=tx1a_utxo,
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sequence=0,
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fee=Decimal("0.1"),
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)["new_utxo"]
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tx2_hex = self.wallet.create_self_transfer_multi(
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utxos_to_spend=[utxo1, utxo2, tx1b_utxo],
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sequence=0,
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amount_per_output=int(COIN * tx1a_utxo["value"]),
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)["hex"]
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# This will raise an exception
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assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, 0)
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def test_new_unconfirmed_inputs(self):
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"""Replacements that add new unconfirmed inputs are rejected"""
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confirmed_utxo = self.make_utxo(self.nodes[0], int(1.1 * COIN))
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unconfirmed_utxo = self.make_utxo(self.nodes[0], int(0.1 * COIN), confirmed=False)
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self.wallet.send_self_transfer(
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from_node=self.nodes[0],
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utxo_to_spend=confirmed_utxo,
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sequence=0,
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fee=Decimal("0.1"),
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)
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tx2_hex = self.wallet.create_self_transfer_multi(
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utxos_to_spend=[confirmed_utxo, unconfirmed_utxo],
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sequence=0,
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amount_per_output=1 * COIN,
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)["hex"]
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# This will raise an exception
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assert_raises_rpc_error(-26, "replacement-adds-unconfirmed", self.nodes[0].sendrawtransaction, tx2_hex, 0)
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def test_too_many_replacements(self):
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"""Replacements that evict too many transactions are rejected"""
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# Try directly replacing more than MAX_REPLACEMENT_LIMIT
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# transactions
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# Start by creating a single transaction with many outputs
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initial_nValue = 10 * COIN
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utxo = self.make_utxo(self.nodes[0], initial_nValue)
|
|
|
|
fee = int(0.0001 * COIN)
|
|
|
|
split_value = int((initial_nValue - fee) / (MAX_REPLACEMENT_LIMIT + 1))
|
|
|
|
|
|
|
|
splitting_tx_utxos = self.wallet.send_self_transfer_multi(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxos_to_spend=[utxo],
|
|
|
|
sequence=0,
|
|
|
|
num_outputs=MAX_REPLACEMENT_LIMIT + 1,
|
|
|
|
amount_per_output=split_value,
|
|
|
|
)["new_utxos"]
|
|
|
|
|
|
|
|
# Now spend each of those outputs individually
|
|
|
|
for utxo in splitting_tx_utxos:
|
|
|
|
self.wallet.send_self_transfer(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxo_to_spend=utxo,
|
|
|
|
sequence=0,
|
|
|
|
fee=Decimal(fee) / COIN,
|
|
|
|
)
|
|
|
|
|
|
|
|
# Now create doublespend of the whole lot; should fail.
|
|
|
|
# Need a big enough fee to cover all spending transactions and have
|
|
|
|
# a higher fee rate
|
|
|
|
double_spend_value = (split_value - 100 * fee) * (MAX_REPLACEMENT_LIMIT + 1)
|
|
|
|
double_tx = self.wallet.create_self_transfer_multi(
|
|
|
|
utxos_to_spend=splitting_tx_utxos,
|
|
|
|
sequence=0,
|
|
|
|
amount_per_output=double_spend_value,
|
|
|
|
)["tx"]
|
|
|
|
double_tx_hex = double_tx.serialize().hex()
|
|
|
|
|
|
|
|
# This will raise an exception
|
|
|
|
assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, double_tx_hex, 0)
|
|
|
|
|
|
|
|
# If we remove an input, it should pass
|
|
|
|
double_tx.vin.pop()
|
|
|
|
double_tx_hex = double_tx.serialize().hex()
|
|
|
|
self.nodes[0].sendrawtransaction(double_tx_hex, 0)
|
|
|
|
|
|
|
|
def test_too_many_replacements_with_default_mempool_params(self):
|
|
|
|
"""
|
|
|
|
Test rule 5 (do not allow replacements that cause more than 100
|
|
|
|
evictions) without having to rely on non-default mempool parameters.
|
|
|
|
|
|
|
|
In order to do this, create a number of "root" UTXOs, and then hang
|
|
|
|
enough transactions off of each root UTXO to exceed the MAX_REPLACEMENT_LIMIT.
|
|
|
|
Then create a conflicting RBF replacement transaction.
|
|
|
|
"""
|
|
|
|
# Clear mempools to avoid cross-node sync failure.
|
|
|
|
for node in self.nodes:
|
|
|
|
self.generate(node, 1)
|
|
|
|
normal_node = self.nodes[1]
|
|
|
|
wallet = MiniWallet(normal_node)
|
|
|
|
|
|
|
|
# This has to be chosen so that the total number of transactions can exceed
|
|
|
|
# MAX_REPLACEMENT_LIMIT without having any one tx graph run into the descendant
|
|
|
|
# limit; 10 works.
|
|
|
|
num_tx_graphs = 10
|
|
|
|
|
|
|
|
# (Number of transactions per graph, rule 5 failure expected)
|
|
|
|
cases = [
|
|
|
|
# Test the base case of evicting fewer than MAX_REPLACEMENT_LIMIT
|
|
|
|
# transactions.
|
|
|
|
((MAX_REPLACEMENT_LIMIT // num_tx_graphs) - 1, False),
|
|
|
|
|
|
|
|
# Test hitting the rule 5 eviction limit.
|
|
|
|
(MAX_REPLACEMENT_LIMIT // num_tx_graphs, True),
|
|
|
|
]
|
|
|
|
|
|
|
|
for (txs_per_graph, failure_expected) in cases:
|
|
|
|
self.log.debug(f"txs_per_graph: {txs_per_graph}, failure: {failure_expected}")
|
|
|
|
# "Root" utxos of each txn graph that we will attempt to double-spend with
|
|
|
|
# an RBF replacement.
|
|
|
|
root_utxos = []
|
|
|
|
|
|
|
|
# For each root UTXO, create a package that contains the spend of that
|
|
|
|
# UTXO and `txs_per_graph` children tx.
|
|
|
|
for graph_num in range(num_tx_graphs):
|
|
|
|
root_utxos.append(wallet.get_utxo())
|
|
|
|
|
|
|
|
optin_parent_tx = wallet.send_self_transfer_multi(
|
|
|
|
from_node=normal_node,
|
|
|
|
sequence=MAX_BIP125_RBF_SEQUENCE,
|
|
|
|
utxos_to_spend=[root_utxos[graph_num]],
|
|
|
|
num_outputs=txs_per_graph,
|
|
|
|
)
|
|
|
|
assert_equal(True, normal_node.getmempoolentry(optin_parent_tx['txid'])['bip125-replaceable'])
|
|
|
|
new_utxos = optin_parent_tx['new_utxos']
|
|
|
|
|
|
|
|
for utxo in new_utxos:
|
|
|
|
# Create spends for each output from the "root" of this graph.
|
|
|
|
child_tx = wallet.send_self_transfer(
|
|
|
|
from_node=normal_node,
|
|
|
|
utxo_to_spend=utxo,
|
|
|
|
)
|
|
|
|
|
|
|
|
assert normal_node.getmempoolentry(child_tx['txid'])
|
|
|
|
|
|
|
|
num_txs_invalidated = len(root_utxos) + (num_tx_graphs * txs_per_graph)
|
|
|
|
|
|
|
|
if failure_expected:
|
|
|
|
assert num_txs_invalidated > MAX_REPLACEMENT_LIMIT
|
|
|
|
else:
|
|
|
|
assert num_txs_invalidated <= MAX_REPLACEMENT_LIMIT
|
|
|
|
|
|
|
|
# Now attempt to submit a tx that double-spends all the root tx inputs, which
|
|
|
|
# would invalidate `num_txs_invalidated` transactions.
|
|
|
|
tx_hex = wallet.create_self_transfer_multi(
|
|
|
|
utxos_to_spend=root_utxos,
|
|
|
|
fee_per_output=10_000_000, # absurdly high feerate
|
|
|
|
)["hex"]
|
|
|
|
|
|
|
|
if failure_expected:
|
|
|
|
assert_raises_rpc_error(
|
|
|
|
-26, "too many potential replacements", normal_node.sendrawtransaction, tx_hex, 0)
|
|
|
|
else:
|
|
|
|
txid = normal_node.sendrawtransaction(tx_hex, 0)
|
|
|
|
assert normal_node.getmempoolentry(txid)
|
|
|
|
|
|
|
|
# Clear the mempool once finished, and rescan the other nodes' wallet
|
|
|
|
# to account for the spends we've made on `normal_node`.
|
|
|
|
self.generate(normal_node, 1)
|
|
|
|
self.wallet.rescan_utxos()
|
|
|
|
|
|
|
|
def test_opt_in(self):
|
|
|
|
"""Replacing should only work if orig tx opted in"""
|
|
|
|
tx0_outpoint = self.make_utxo(self.nodes[0], int(1.1 * COIN))
|
|
|
|
|
|
|
|
# Create a non-opting in transaction
|
|
|
|
tx1a_utxo = self.wallet.send_self_transfer(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxo_to_spend=tx0_outpoint,
|
|
|
|
sequence=SEQUENCE_FINAL,
|
|
|
|
fee=Decimal("0.1"),
|
|
|
|
)["new_utxo"]
|
|
|
|
|
|
|
|
# This transaction isn't shown as replaceable
|
|
|
|
assert_equal(self.nodes[0].getmempoolentry(tx1a_utxo["txid"])['bip125-replaceable'], False)
|
|
|
|
|
|
|
|
# Shouldn't be able to double-spend
|
|
|
|
tx1b_hex = self.wallet.create_self_transfer(
|
|
|
|
utxo_to_spend=tx0_outpoint,
|
|
|
|
sequence=0,
|
|
|
|
fee=Decimal("0.2"),
|
|
|
|
)["hex"]
|
|
|
|
|
|
|
|
# This will raise an exception
|
|
|
|
assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx1b_hex, 0)
|
|
|
|
|
|
|
|
tx1_outpoint = self.make_utxo(self.nodes[0], int(1.1 * COIN))
|
|
|
|
|
|
|
|
# Create a different non-opting in transaction
|
|
|
|
tx2a_utxo = self.wallet.send_self_transfer(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxo_to_spend=tx1_outpoint,
|
|
|
|
sequence=0xfffffffe,
|
|
|
|
fee=Decimal("0.1"),
|
|
|
|
)["new_utxo"]
|
|
|
|
|
|
|
|
# Still shouldn't be able to double-spend
|
|
|
|
tx2b_hex = self.wallet.create_self_transfer(
|
|
|
|
utxo_to_spend=tx1_outpoint,
|
|
|
|
sequence=0,
|
|
|
|
fee=Decimal("0.2"),
|
|
|
|
)["hex"]
|
|
|
|
|
|
|
|
# This will raise an exception
|
|
|
|
assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx2b_hex, 0)
|
|
|
|
|
|
|
|
# Now create a new transaction that spends from tx1a and tx2a
|
|
|
|
# opt-in on one of the inputs
|
|
|
|
# Transaction should be replaceable on either input
|
|
|
|
|
|
|
|
tx3a_txid = self.wallet.send_self_transfer_multi(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxos_to_spend=[tx1a_utxo, tx2a_utxo],
|
|
|
|
sequence=[SEQUENCE_FINAL, 0xfffffffd],
|
|
|
|
fee_per_output=int(0.1 * COIN),
|
|
|
|
)["txid"]
|
|
|
|
|
|
|
|
# This transaction is shown as replaceable
|
|
|
|
assert_equal(self.nodes[0].getmempoolentry(tx3a_txid)['bip125-replaceable'], True)
|
|
|
|
|
|
|
|
self.wallet.send_self_transfer(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxo_to_spend=tx1a_utxo,
|
|
|
|
sequence=0,
|
|
|
|
fee=Decimal("0.4"),
|
|
|
|
)
|
|
|
|
|
|
|
|
# If tx3b was accepted, tx3c won't look like a replacement,
|
|
|
|
# but make sure it is accepted anyway
|
|
|
|
self.wallet.send_self_transfer(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxo_to_spend=tx2a_utxo,
|
|
|
|
sequence=0,
|
|
|
|
fee=Decimal("0.4"),
|
|
|
|
)
|
|
|
|
|
|
|
|
def test_prioritised_transactions(self):
|
|
|
|
# Ensure that fee deltas used via prioritisetransaction are
|
|
|
|
# correctly used by replacement logic
|
|
|
|
|
|
|
|
# 1. Check that feeperkb uses modified fees
|
|
|
|
tx0_outpoint = self.make_utxo(self.nodes[0], int(1.1 * COIN))
|
|
|
|
|
|
|
|
tx1a_txid = self.wallet.send_self_transfer(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxo_to_spend=tx0_outpoint,
|
|
|
|
sequence=0,
|
|
|
|
fee=Decimal("0.1"),
|
|
|
|
)["txid"]
|
|
|
|
|
|
|
|
# Higher fee, but the actual fee per KB is much lower.
|
|
|
|
tx1b_hex = self.wallet.create_self_transfer_multi(
|
|
|
|
utxos_to_spend=[tx0_outpoint],
|
|
|
|
sequence=0,
|
|
|
|
num_outputs=100,
|
|
|
|
amount_per_output=int(0.00001 * COIN),
|
|
|
|
)["hex"]
|
|
|
|
|
|
|
|
# Verify tx1b cannot replace tx1a.
|
|
|
|
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, 0)
|
|
|
|
|
|
|
|
# Use prioritisetransaction to set tx1a's fee to 0.
|
|
|
|
self.nodes[0].prioritisetransaction(txid=tx1a_txid, fee_delta=int(-0.1 * COIN))
|
|
|
|
|
|
|
|
# Now tx1b should be able to replace tx1a
|
|
|
|
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, 0)
|
|
|
|
|
|
|
|
assert tx1b_txid in self.nodes[0].getrawmempool()
|
|
|
|
|
|
|
|
# 2. Check that absolute fee checks use modified fee.
|
|
|
|
tx1_outpoint = self.make_utxo(self.nodes[0], int(1.1 * COIN))
|
|
|
|
|
|
|
|
# tx2a
|
|
|
|
self.wallet.send_self_transfer(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxo_to_spend=tx1_outpoint,
|
|
|
|
sequence=0,
|
|
|
|
fee=Decimal("0.1"),
|
|
|
|
)
|
|
|
|
|
|
|
|
# Lower fee, but we'll prioritise it
|
|
|
|
tx2b = self.wallet.create_self_transfer(
|
|
|
|
utxo_to_spend=tx1_outpoint,
|
|
|
|
sequence=0,
|
|
|
|
fee=Decimal("0.09"),
|
|
|
|
)
|
|
|
|
|
|
|
|
# Verify tx2b cannot replace tx2a.
|
|
|
|
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx2b["hex"], 0)
|
|
|
|
|
|
|
|
# Now prioritise tx2b to have a higher modified fee
|
|
|
|
self.nodes[0].prioritisetransaction(txid=tx2b["txid"], fee_delta=int(0.1 * COIN))
|
|
|
|
|
|
|
|
# tx2b should now be accepted
|
|
|
|
tx2b_txid = self.nodes[0].sendrawtransaction(tx2b["hex"], 0)
|
|
|
|
|
|
|
|
assert tx2b_txid in self.nodes[0].getrawmempool()
|
|
|
|
|
|
|
|
def test_rpc(self):
|
|
|
|
us0 = self.wallet.get_utxo()
|
|
|
|
ins = [us0]
|
|
|
|
outs = {ADDRESS_BCRT1_UNSPENDABLE: Decimal(1.0000000)}
|
|
|
|
rawtx0 = self.nodes[0].createrawtransaction(ins, outs, 0, True)
|
|
|
|
rawtx1 = self.nodes[0].createrawtransaction(ins, outs, 0, False)
|
|
|
|
json0 = self.nodes[0].decoderawtransaction(rawtx0)
|
|
|
|
json1 = self.nodes[0].decoderawtransaction(rawtx1)
|
|
|
|
assert_equal(json0["vin"][0]["sequence"], 4294967293)
|
|
|
|
assert_equal(json1["vin"][0]["sequence"], 4294967295)
|
|
|
|
|
|
|
|
if self.is_specified_wallet_compiled():
|
|
|
|
self.init_wallet(node=0)
|
|
|
|
rawtx2 = self.nodes[0].createrawtransaction([], outs)
|
|
|
|
frawtx2a = self.nodes[0].fundrawtransaction(rawtx2, {"replaceable": True})
|
|
|
|
frawtx2b = self.nodes[0].fundrawtransaction(rawtx2, {"replaceable": False})
|
|
|
|
|
|
|
|
json0 = self.nodes[0].decoderawtransaction(frawtx2a['hex'])
|
|
|
|
json1 = self.nodes[0].decoderawtransaction(frawtx2b['hex'])
|
|
|
|
assert_equal(json0["vin"][0]["sequence"], 4294967293)
|
|
|
|
assert_equal(json1["vin"][0]["sequence"], 4294967294)
|
|
|
|
|
|
|
|
def test_no_inherited_signaling(self):
|
|
|
|
confirmed_utxo = self.wallet.get_utxo()
|
|
|
|
|
|
|
|
# Create an explicitly opt-in parent transaction
|
|
|
|
optin_parent_tx = self.wallet.send_self_transfer(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxo_to_spend=confirmed_utxo,
|
|
|
|
sequence=MAX_BIP125_RBF_SEQUENCE,
|
|
|
|
fee_rate=Decimal('0.01'),
|
|
|
|
)
|
|
|
|
assert_equal(True, self.nodes[0].getmempoolentry(optin_parent_tx['txid'])['bip125-replaceable'])
|
|
|
|
|
|
|
|
replacement_parent_tx = self.wallet.create_self_transfer(
|
|
|
|
utxo_to_spend=confirmed_utxo,
|
|
|
|
sequence=MAX_BIP125_RBF_SEQUENCE,
|
|
|
|
fee_rate=Decimal('0.02'),
|
|
|
|
)
|
|
|
|
|
|
|
|
# Test if parent tx can be replaced.
|
|
|
|
res = self.nodes[0].testmempoolaccept(rawtxs=[replacement_parent_tx['hex']])[0]
|
|
|
|
|
|
|
|
# Parent can be replaced.
|
|
|
|
assert_equal(res['allowed'], True)
|
|
|
|
|
|
|
|
# Create an opt-out child tx spending the opt-in parent
|
|
|
|
parent_utxo = self.wallet.get_utxo(txid=optin_parent_tx['txid'])
|
|
|
|
optout_child_tx = self.wallet.send_self_transfer(
|
|
|
|
from_node=self.nodes[0],
|
|
|
|
utxo_to_spend=parent_utxo,
|
|
|
|
sequence=SEQUENCE_FINAL,
|
|
|
|
fee_rate=Decimal('0.01'),
|
|
|
|
)
|
|
|
|
|
|
|
|
# Reports true due to inheritance
|
|
|
|
assert_equal(True, self.nodes[0].getmempoolentry(optout_child_tx['txid'])['bip125-replaceable'])
|
|
|
|
|
|
|
|
replacement_child_tx = self.wallet.create_self_transfer(
|
|
|
|
utxo_to_spend=parent_utxo,
|
|
|
|
sequence=SEQUENCE_FINAL,
|
|
|
|
fee_rate=Decimal('0.02'),
|
|
|
|
)
|
|
|
|
|
|
|
|
# Broadcast replacement child tx
|
|
|
|
# BIP 125 :
|
|
|
|
# 1. The original transactions signal replaceability explicitly or through inheritance as described in the above
|
|
|
|
# Summary section.
|
|
|
|
# The original transaction (`optout_child_tx`) doesn't signal RBF but its parent (`optin_parent_tx`) does.
|
|
|
|
# The replacement transaction (`replacement_child_tx`) should be able to replace the original transaction.
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# See CVE-2021-31876 for further explanations.
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assert_equal(True, self.nodes[0].getmempoolentry(optin_parent_tx['txid'])['bip125-replaceable'])
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assert_raises_rpc_error(-26, 'txn-mempool-conflict', self.nodes[0].sendrawtransaction, replacement_child_tx["hex"], 0)
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self.log.info('Check that the child tx can still be replaced (via a tx that also replaces the parent)')
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replacement_parent_tx = self.wallet.send_self_transfer(
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from_node=self.nodes[0],
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utxo_to_spend=confirmed_utxo,
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sequence=SEQUENCE_FINAL,
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fee_rate=Decimal('0.03'),
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)
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# Check that child is removed and update wallet utxo state
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assert_raises_rpc_error(-5, 'Transaction not in mempool', self.nodes[0].getmempoolentry, optout_child_tx['txid'])
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self.wallet.get_utxo(txid=optout_child_tx['txid'])
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def test_replacement_relay_fee(self):
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tx = self.wallet.send_self_transfer(from_node=self.nodes[0])['tx']
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# Higher fee, higher feerate, different txid, but the replacement does not provide a relay
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# fee conforming to node's `incrementalrelayfee` policy of 1000 sat per KB.
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assert_equal(self.nodes[0].getmempoolinfo()["incrementalrelayfee"], Decimal("0.00001"))
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tx.vout[0].nValue -= 1
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assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx.serialize().hex())
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def test_fullrbf(self):
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confirmed_utxo = self.make_utxo(self.nodes[0], int(2 * COIN))
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self.restart_node(0, extra_args=["-mempoolfullrbf=1"])
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assert self.nodes[0].getmempoolinfo()["fullrbf"]
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# Create an explicitly opt-out transaction
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optout_tx = self.wallet.send_self_transfer(
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from_node=self.nodes[0],
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utxo_to_spend=confirmed_utxo,
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sequence=MAX_BIP125_RBF_SEQUENCE + 1,
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fee_rate=Decimal('0.01'),
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)
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assert_equal(False, self.nodes[0].getmempoolentry(optout_tx['txid'])['bip125-replaceable'])
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conflicting_tx = self.wallet.create_self_transfer(
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utxo_to_spend=confirmed_utxo,
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sequence=SEQUENCE_FINAL,
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fee_rate=Decimal('0.02'),
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)
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# Send the replacement transaction, conflicting with the optout_tx.
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self.nodes[0].sendrawtransaction(conflicting_tx['hex'], 0)
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# Optout_tx is not anymore in the mempool.
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assert optout_tx['txid'] not in self.nodes[0].getrawmempool()
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assert conflicting_tx['txid'] in self.nodes[0].getrawmempool()
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if __name__ == '__main__':
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ReplaceByFeeTest(__file__).main()
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